A current of 0.5 Ampere flows through a

resistance when 6 Volt is applied. To change the

current to 0.25 Ampere, you must:

a) increased the supply to 12 Volt

b} reduced the supply to 3 Volt

c) connect a 1252 resistor in parallel with ' the existing resistance

d) connect a 6S2 resistor in parallel with the

existing resistor

Answer is B- reduced the supply to 3 Volt

solution:-

Remember the ohm's law formula.

V= IR V is voltage, I is current and R is resistor.

Given I= 0.5A, V= 6v R = ?

V= IR, get R

R= V/R, R= 6v/0.5A

= 12 ohm

if change current to 0.25amp. logically voltage must reduce

given I= 0.25A, v=? and R= 12 ohm

formula V=IR

so V= 0.25A (12 ohm)

= 3v

Check back V=IR

3v= I (12 ohm)

3v/12 ohm = I

so I = 0.25A

The maximum output power permitted from

a Class A amateur radio station is:

a) 300 Watt PEP

b) 400 Watt PEP

c) 500 Watt PEP

d) 1000 Watt PEP

Answer is B- 400 watt pep

refer Class A license:-

## 3 comments:

peksa kat SACC convention center plak kali ni ek..shah alam.

oooo ya ka. tku bro info tu

SACC con. center,

no 4,jalan perbadanan 14/9

40000 Shah Alam,Selangor.

alamat latest setakat ni,wallahualam kala nak dituko lain kelak...

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